简单有效的防制垃圾引用(第1版)
简单有效的防制垃圾引用(第1版)
我只加在了日记页面。其他页面我正在找。
效果
引用通告地址: trackback.asp?tbID=JNKPQRI8
论坛下载不了的可以到我的BLOG下载
具体方法如下。
===========================================================
文件trackback.asp
查找
tbID = CheckStr(Request.QueryString("tbID"))
替换成
tbID = Decrypt(CheckStr(Request.QueryString("tbID")))
********可以不换***********
查找
Response.Redirect("search.asp?searchType=trackback")
替换成
Response.contentType="text/xml"
Response.write "<?xml version=""1.0"" encoding=""UTF-8""?><?xml-stylesheet type=""text/xsl"" href=""tb.xsl""?>"
%>
<response><error>1</error><message>日志ID错误.请检查......</message></response>
<%
查找
<response><error>1</error><message>日志没有被引用.</message></response>
替换成
<response><error>1</error><message>日志(ID=<% Response.write tbID %>)没有被引用.</message></response>
********可以不换***********
===========================================================
文件class\cls_article.asp
查找
引用通告地址:</strong> <a href="<%=(SiteURL&"trackback.asp?tbID="&id)%>" target="_blank"><%=(SiteURL&"trackback.asp?tbID="&id)%></a>
替换成
引用通告地址:</strong> <a href="<%=(SiteURL&"trackback.asp?tbID="&Encrypt(id))%>" target="_blank"><%=(SiteURL&"trackback.asp?tbID="&Encrypt(id))%>
查找
<a href=""trackback.asp?action=deltb&tbID="&commArr(6,Pcount)&"&logID="&LogID&"""
替换成
<a href=""trackback.asp?action=deltb&tbID="&Encrypt(commArr(6,Pcount))&"&logID="&LogID&"""
===========================================================
文件common\function.asp
在文件最后,%>的上面添加
Function Encrypt(theNumber)
On Error Resume Next
Dim n, szEnc, t, HiN, LoN, i
n = CDbl((theNumber + 1570) ^ 2 - 7 * (theNumber + 1570) - 450)
If n < 0 Then szEnc = "R" Else szEnc = "J"
n = CStr(abs(n))
For i = 1 To Len(n) step 2
t = Mid(n, i, 2)
If Len(t) = 1 Then
szEnc = szEnc & t
Exit For
End If
HiN = (CInt(t) And 240) / 16
LoN = CInt(t) And 15
szEnc = szEnc & Chr(Asc("M") + HiN) & Chr(Asc("C") + LoN)
Next
Encrypt = szEnc
End Function
Function Decrypt(theNumber)
On Error Resume Next
Dim e, n, sign, t, HiN, LoN, NewN, i
e = theNumber
If Left(e, 1) = "R" Then sign = -1 Else sign = 1
e = Mid(e, 2)
NewN = ""
For i = 1 To Len(e) step 2
t = Mid(e, i, 2)
If Asc(t) >= Asc("0") And Asc(t) <= Asc("9") Then
NewN = NewN & t
Exit For
End If
HiN = Mid(t, 1, 1)
LoN = Mid(t, 2, 1)
HiN = (Asc(HiN) - Asc("M")) * 16
LoN = Asc(LoN) - Asc("C")
t = CStr(HiN Or LoN)
If Len(t) = 1 Then t = "0" & t
NewN = NewN & t
Next
e = CDbl(NewN) * sign
Decrypt = CLng((7 + sqr(49 - 4 * (-450 - e))) / 2 - 1570)
End Function
=============================================================
其他页面我还没有加。请大家一起找找。
演示自己找。都有人说我大AD了。
没有修改过这3个文件的用户可以下载下面的覆盖即可。
[ 本帖最后由 向导 于 2007-1-3 08:25 编辑 ]
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